# Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?

Aug 23, 2016

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

${V}_{2} \cong 30 L$

#### Explanation:

${V}_{2}$ $=$ $\frac{{P}_{1} {V}_{1} {T}_{2}}{{P}_{2} {T}_{1}}$

$\frac{12 \cdot a t m \times 23 \cdot L \times 300 K}{14 \cdot a t m \times 200 \cdot K}$ $=$ ??L

The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.