Inside a bag are 6 red, 4 orange, 7 yellow, 3 purple and 4 green Skittles. What is the probability of drawing a green Skittle, replacing it, and then drawing another green Skittle?

May 7, 2018

Probability of drawing a green Skittle, replacing it, and then drawing another green Skittle is $\frac{1}{36}$.

Explanation:

As there are $4$ green Skittles among a total of $24$ Skittles,

probability of drawing a green Skittle is $\frac{4}{24} = \frac{1}{6}$

When this is replaced, we again have $4$ green Skittles among a total of $24$ Skittles and hence probability of drawing another green Skittle is again $\frac{1}{6}$.

Hence probability of drawing a green Skittle, replacing it, and then drawing another green Skittle is $\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}$.