Is it possible to for an integral in the form #int_a^oo f(x)\ dx#, and #lim_(x->oo)f(x)!=0#, to still be convergent?
If you view the integral as the area under the curve, it seems logical that there is no way that the integral
#int_a^oo f(x)\ dx#
would converge unless #f(x)# eventually tends to zero
#lim_(x->oo)f(x)=0#
since the area under the graph wouldn't be bounded otherwise.
My question is, are there integrals where this is not the case? Where the limit of the function doesn't go to zero, but the integral is still convergent? What would be an example of such function?
If you view the integral as the area under the curve, it seems logical that there is no way that the integral
would converge unless
since the area under the graph wouldn't be bounded otherwise.
My question is, are there integrals where this is not the case? Where the limit of the function doesn't go to zero, but the integral is still convergent? What would be an example of such function?
1 Answer
If the limit
In fact suppose
So:
and based on a well known inequality:
which clearly diverges for
If
For the same reason, also if
However, if
Can't find a counterexample right now, though.