Is this equation #2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i }# balanced?

1 Answer
Sep 13, 2017

Answer:

No.

Explanation:

No.

A balanced equation displays an equal amount of atoms of each element on both sides of the yield arrow.

From what you gave us/me, there are:

  • #2# #Al# atoms on the reactant's side, but only #1# on the product's.
  • an equal amount of #Ni# atoms, with #3# atoms on each side... unless the product's #Ni# is not a typo and is supposed to be #N_"i"#.
  • #2# #Br# atoms on the reactant's side and #3# on the product's... unless it's supposed to be #B# (boron).

In order to balance this equation, we have to play around with the coefficients so that each atom on the reactant's is equal to the to product's.

You should get this:

#2Al + 3NiBr_"2" -> 2AlBr_"3" + 3Ni#

Now if we look at this equation, there are an equal amount of every atom on both sides of the yield arrow.

Hope this helps :)