# Is this equation 2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i } balanced?

Sep 13, 2017

No.

#### Explanation:

No.

A balanced equation displays an equal amount of atoms of each element on both sides of the yield arrow.

From what you gave us/me, there are:

• $2$ $A l$ atoms on the reactant's side, but only $1$ on the product's.
• an equal amount of $N i$ atoms, with $3$ atoms on each side... unless the product's $N i$ is not a typo and is supposed to be ${N}_{\text{i}}$.
• $2$ $B r$ atoms on the reactant's side and $3$ on the product's... unless it's supposed to be $B$ (boron).

In order to balance this equation, we have to play around with the coefficients so that each atom on the reactant's is equal to the to product's.

You should get this:

$2 A l + 3 N i B {r}_{\text{2" -> 2AlBr_"3}} + 3 N i$

Now if we look at this equation, there are an equal amount of every atom on both sides of the yield arrow.

Hope this helps :)