# Is this how a single integral works?

## ${\int}_{b}^{a}$$\left(c\right)$$\mathrm{dx}$$=$$a$$\times$c$-$$b$$\times$$c$

Assuming $c$ in the given equation is not dependent on the variable $x ,$ LHS of given integral becomes
${\int}_{b}^{a}$$\left(c\right)$$\mathrm{dx}$
$c {\int}_{b}^{a} \mathrm{dx} = c {\left[x\right]}_{b}^{a}$
$\implies c \left(a - b\right)$
$\implies c \times a - b \times c = \text{RHS}$