# It takes 23.5 kJ of heat energy to raise the temperature of 100 g of a substance by 50°C. What is the substance?

Mar 28, 2016

Most probably liquid ammonia.

#### Explanation:

Heat energy $W = m c \Delta T$

$\therefore c = \frac{W}{m \Delta T}$

$= \frac{23500 J}{0.1 k g \times 50 K}$

$= 4700 J / k g . K$.

Consultation of a standard data sheet for specific heat capacities reveals that this substance is most probably $N {H}_{3 \left(l\right)}$.