Let #f(x)=1-x# and #g(x)= x^2# and #h(x)= 1/x#, how do you find g(h(x))?

1 Answer
Jun 5, 2015

If #g(x) = x^2#
and #h(x) = 1/x#

then #g(h(x)) = (h(x))^2 = (1/x)^2 = 1/x^2#

Sometimes this can be easier to see if you remember that the #x# in
#color(white)("XXXX")##g(x)=x^2# and in #h(x)= 1/x#
are just place holders
and could be written as
#color(white)("XXXX")##g(W) = W^2# and #h(Q)=1/Q#
then there is less confusion in replacing the #W# of #g(W)# with #h(x)#