# Light is travelling at a speed of 2.29*10^8 m/s through ice. What is the index of refraction of ice?

Sep 6, 2016

$1.31$

#### Explanation:

We know that
Refractive index of a medium $n$ $= \left(\text{Velocity of light in Vacuum "c)/("Velocity of light in medium}\right)$
Inserting given value and taking $c = 3 \times {10}^{8} m {s}^{-} 1$, we get

Refractive index of ice $n = \frac{3 \times {10}^{8}}{2.29 \times {10}^{8}}$

$\implies n = 1.31$