# On a flat surface a 25kg crate is pushed at a constant velocity with a force of 50N. Determine the coefficient of friction. What would the acceleration on the crate be if the applied force was doubled?

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and how far would the crate move in the 5 seconds if it began with a velocity of 2m/s?

and how far would the crate move in the 5 seconds if it began with a velocity of 2m/s?

##### 1 Answer

#### Answer:

#### Explanation:

Since the crate is moving at constant velocity the net force on the crate is zero.

The frictional force due to the surface is given by:

Since the crate is moving we are referring to the coefficient of dynamic friction.

**mg**.

The frictional force is balanced by the effort so:

The effort is now doubled so the forces on the block are not balanced.

The net force is given by:

Using Newton's Law:

I will assume you mean how far the crate moves after the force has been doubled.

Using the equation of motion:

Putting in the numbers: