Oxygen gas is at STP when it occupies a volume 5.5 liters. To what temperature should it be raised to occupy a volume of 9.0 liters?

1 Answer
May 26, 2018

Answer:

Well...for a given quantity of gas (such as we gots here)….

#VpropT#

Explanation:

And this is old #"Charles' Law..."#

Now #"STP"# specifies (depending on your syllabus) #298*K# and (near to) #1*atm#...

Given #VpropT#, #V=kT#...solving for #k#, #k=V/T#...but this should apply at all temperatures for a given quantity of gas...and so...

#V_1/T_1=V_2/T_2#...and we solve for #T_2=(V_2xxT_1)/V_1#

#-=(9.0*Lxx273.15*K)/(5.5*L)=447.0*K-=173.8# #""^@C#