Prove: e^(i pi)+1=0 "?"

Mar 10, 2018

${e}^{i \theta}$ is exponential form of a complex number, which in trigonometric form is written as $\cos \theta + i \sin \theta$. Hence,
${e}^{i \pi} + 1 = \cos \pi + i \sin \pi + 1$
= $- 1 + i \cdot 0 + 1$
= $0$