# Pure gold has a density of 19.32 g/cm3. How large would a piece of gold be if it had a mass of 318.97 g?

Aug 29, 2017

The volume of the sample of gold is ${\text{16.51 cm}}^{3}$.

#### Explanation:

The formula for density is:

$D = \frac{M}{V}$,

where:

$D$ is density, $M$ is mass, and $V$ is volume.

Rearrange the density formula to isolate volume.

$V = \frac{M}{D}$

$V = \left(318.97 \text{g Au")/(19.32"g"/"cm"^3}\right)$

V=318.97color(red)cancel(color(black)("g Au"))xx(1"cm"^3 "Au")/(19.32color(red)cancel(color(black)("g Au"))) $\leftarrow$ Multiply by the multiplicative inverse of the density.

$V = \text{16.51 cm"^3 "Au}$