Pure gold has a density of 19.32 g/cm3. How large would a piece of gold be if it had a mass of 318.97 g?

1 Answer
Meave60
Aug 29, 2017

The volume of the sample of gold is #"16.51 cm"^3#.

Explanation:

The formula for density is:

#D=M/V#,

where:

#D# is density, #M# is mass, and #V# is volume.

Rearrange the density formula to isolate volume.

#V=M/D#

#V=(318.97"g Au")/(19.32"g"/"cm"^3")#

#V=318.97color(red)cancel(color(black)("g Au"))xx(1"cm"^3 "Au")/(19.32color(red)cancel(color(black)("g Au")))# #larr# Multiply by the multiplicative inverse of the density.

#V="16.51 cm"^3 "Au"#

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