Question

Radium, Ra-226, undergoes alpha decay. What is the product?

Answer 1

Well, an `alpha-"particle"-=""_2^4He^(2+)`

Explanation:

And mass and charge are (almost conserved) in nucular reactions...

`""_88^226Rararr""_86^222Rn+""_2^4He^(2+) + 2e^(-)`...

...and congratulations, I think this is the first time for a long time that I have had to look up an elemental symbol on the Table....I thought for a moment that `"radon"-="Rd"`