Rubidium (Rb) has an atomic number of 37. It can lose 1 electron to form an ion. What would its charge be?

1 Answer
Feb 5, 2017


Rb +


Rb atom has 37 electrons and 37 protons. when 1 electron is removed number of protons remains 37 but number of electrons is 36.36 negative charges is balanced by 36 positive charges. one extra proton is present so 1 positive charge.