# Slope of a curve y=x^2-3 at the point where x=1?

First you need to find $f ' \left(x\right)$, which is the derivative of $f \left(x\right)$.
$f ' \left(x\right) = 2 x - 0 = 2 x$
Second, substitute in the value of x, in this case $x = 1$.
$f ' \left(1\right) = 2 \left(1\right) = 2$
The slope of the curve $y = {x}^{2} - 3$ at the $x$ value of $1$ is $2$.