Slope of a Curve at a Point
Key Questions
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The slope of a curve of
y=f(x)y=f(x) atx=ax=a isf'(a) .Let us find the slope of
f(x)=x^3-x+2 atx=1 .By taking the derivative,
f'(x)=3x^2-1 By plugging in
x=1 ,
f'(1)=3(1)^2-1=2 Hence, the slope is
2 . -
First you need to find
f'(x) , which is the derivative off(x) .f'(x)=2x-0=2x Second, substitute in the value of x, in this case
x=1 .f'(1)=2(1)=2 The slope of the curve
y=x^2-3 at thex value of1 is2 . -
Answer:
See below
Explanation:
In every courve's point , the slope of a courve is defined by the tangent line in that point. See picture
Questions
Derivatives
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Tangent Line to a Curve
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Normal Line to a Tangent
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Slope of a Curve at a Point
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Average Velocity
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Instantaneous Velocity
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Limit Definition of Derivative
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First Principles Example 1: x²
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First Principles Example 2: x³
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First Principles Example 3: square root of x
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Standard Notation and Terminology
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Differentiable vs. Non-differentiable Functions
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Rate of Change of a Function
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Average Rate of Change Over an Interval
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Instantaneous Rate of Change at a Point