Slope of a Curve at a Point

Key Questions

  • The slope of a curve of y=f(x)y=f(x) at x=ax=a is f'(a).

    Let us find the slope of f(x)=x^3-x+2 at x=1.

    By taking the derivative,
    f'(x)=3x^2-1

    By plugging in x=1,
    f'(1)=3(1)^2-1=2

    Hence, the slope is 2.

  • First you need to find f'(x), which is the derivative of f(x).

    f'(x)=2x-0=2x

    Second, substitute in the value of x, in this case x=1.

    f'(1)=2(1)=2

    The slope of the curve y=x^2-3 at the x value of 1 is 2.

  • Answer:

    See below

    Explanation:

    In every courve's point , the slope of a courve is defined by the tangent line in that point. See picture

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Questions