Starting with 189 grams of uranium-238, after one half life has gone by, how many grams of uranium-238 will remain?

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Starting with 189 grams of uranium-238, after one half life has gone by, how many grams of uranium-238 will remain?

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Answer 1 · 2017-09-13T13:24:54

95.5 g

Explanation:

To solve half life problems we need the formula:
$mass after (n) number of half lives = {(\frac{1}{2})}^{n} \cdot original mass$ $"mass after (n) number of half lives"= (1/2)^n *"original mass"$

In your example only one half time passed, therefore:
$m a s s = {(\frac{1}{2})}^{1} \cdot original mass = \frac{1}{2} \cdot 189 grams = 95.5 g$ $mass= (1/2)^1 * "original mass" = 1/2 * 189 "grams"= 95.5 g$

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Starting with 189 grams of uranium-238, after one half life has gone by, how many grams of uranium-238 will remain?

1 Answer

Explanation:

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