# The area of a rectangle is 45 square cm. If the length is 4cm greater than the width, what are the dimension of the rectangle?

The length & width of rectangle are $9 \mathmr{and} 5$ cms respectively.
Let the width of the rectangle be $x$ cm; then the length will be $x + 4$cm. Area of the rectangle is $x \cdot \left(x + 4\right) = 45 \mathmr{and} {x}^{2} + 4 x - 45 = 0 \mathmr{and} \left(x + 9\right) \left(x - 5\right) = 0 \therefore x = - 9 \mathmr{and} x = 5$Width cannot be negative. So x=5; x+4=9:.The length & width are $9 \mathmr{and} 5$ cms respectively.[Ans]