The area of a rectangle is 65yd^2 , and the length of the rectangle is 3yd less than double the width, how do you find the dimensions?
build the equations and solve...
let the area be
so 1.st equqtion will be
and length is 3 yd less than double the width says:
now we have a 2nd order equation just find the roots and take the positive one as width can not be negative...