# The area of a rectangle is 65yd^2 , and the length of the rectangle is 3yd less than double the width, how do you find the dimensions?

##### 1 Answer

Sep 29, 2016

build the equations and solve...

#### Explanation:

let the area be

so 1.st equqtion will be

and length is 3 yd less than double the width says:

replacing

now we have a 2nd order equation just find the roots and take the positive one as width can not be negative...

replacing