# The area of this rectangle is 56 square units. How do you find its length x-5 and width x+5?

$x = 9$
$\left(x - 5\right) \cdot \left(x + 5\right) = 56$
${x}^{2} - 25 = 56$
${x}^{2} = 81 \implies x = 9$