The base of a triangular pyramid is a triangle with corners at $(4 ,1 )$ , $(3 ,1 )$ , and $(9 ,5 )$ . If the pyramid has a height of $8$ , what is the pyramid's volume?

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Answer 1 · 2016-12-31T01:56:15

$16/3=5.33$

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Pyramid volume $V=1/3*A*H$ , where $A$ is the pyramid's base area and $H$ is the height of the pyramid.

Given that $A(3,1), B(4,1) and C((,5)$ are the triangular base's corners, as shown in the diagram,
$=> A=1/2*1*4=2$

Given that the pyramid has a height of $8, => H=8$

$=> V=1/3AH=1/3*2*8=16/3=5.33$

The base of a triangular pyramid is a triangle with corners at (4 ,1 )(4 ,1 ), (3 ,1 )(3 ,1 ), and (9 ,5 )(9 ,5 ). If the pyramid has a height of 8 8 , what is the pyramid's volume?