The base of a triangular pyramid is a triangle with corners at $(5 ,8 )$ , $(3 ,4 )$ , and $(4 ,8 )$ . If the pyramid has a height of $6$ , what is the pyramid's volume?

Question

1607 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-21T05:28:48

$V=4" "$ cubic units

To solve for the volume of the pyramid which is
$V=1/3*area*height$

Solve for the area of the triangle first with $P_1(3, 4),P_2(5, 8),P_3(4, 8)$

the area A matrix

$A=1/2*[(x_1,x_2,x_3,x_1),(y_1,y_2,y_3,y_1)]$

$A=1/2*(x_1*y_2+x_2*y_3+x_3*y_1-x_2*y_1-x_3*y_2-x_1*y_3)$

$A=1/2*[(3,5,4,3),(4,8,8,4)]$

$A=1/2*[3(8)+5(8)+4(4)-5(4)-4(8)-3(8)]$

$A=1/2*(24+40+16-20-32-24)$

$A=1/2*(80-76)$

$A=2$

Now the volume V

$V=1/3*area*height$

$V=1/3*2*6=4$

$V=4" "$ cubic units

God bless....I hope the explanation is useful.

The base of a triangular pyramid is a triangle with corners at (5 ,8 )(5 ,8 ), (3 ,4 )(3 ,4 ), and (4 ,8 )(4 ,8 ). If the pyramid has a height of 6 6 , what is the pyramid's volume?