# The carbon dioxide molecule contains how many double bonds?

Jun 16, 2018

$\text{Two...?}$

#### Explanation:

We got carbon dioxide, with $2 \times {6}_{\text{oxygen"+1xx4_"carbon}}$ valence electrons to distribute...i.e. 8 electron pairs over the three centres...

:ddotO=C=stackrel(ddot)O:

Formally, the carbon centre is $\text{sp-hybridized}$, whereas each oxygen centre is $\text{sp"^2"-hybridized}$, and thus $\angle O - C - O = {180}^{\circ}$.

And clearly, the two $C - O$ $\pi - \text{bonds}$ ARE ORTHOGONAL to each other.