# The concentration of carbon monoxide in an urban apartment is 48 mug/m^3. What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

Sep 1, 2016

Approx. $5$ $m g$

#### Explanation:

$\text{1 metre = 3.048 feet}$

Volume of room $=$ $10.6 \times 14.8 \times 20.5 \cdot f {t}^{3} \times \frac{1}{3.048 \cdot f t \cdot {m}^{-} 1} ^ 3$

$=$ $113.57 \cdot {m}^{3}$

And thus mass of $C O$ $=$ $113.57 \cdot {m}^{3} \times 48 \times {10}^{-} 6 \cdot g \cdot {m}^{-} 3$

$=$ $5.45 \times {10}^{-} 3 g$

Do not assume that I have got my arithmetic right; you are obliged to check this result.