# The curve has a parametric equation of #x=(t^3)-12t# and #y=3(t^2)#, how would you find the two points the parameter t=2 crosses the curve?

##### 1 Answer

Oct 7, 2017

We have parametric equations:

# x= t^3 - 12t #

# y = 3t^2 #

When

# x= 8 - 24 = -16#

# y = 3*4 \ \ \ \ = 12 #

So, there is only one point associated with

The graph of the curve is as follows: