# The density of silver (Ag) is 10.5 g/cm^3. How do you find the mass of Ag that occupies 965 cm^3 of space?

Aug 28, 2016

1.01 xx10^(4 grams

#### Explanation:

To calculate the mass of the $A g$, we have to use this formula:

- Usually, density will have units of $\frac{g}{m L}$ when dealing with a liquid or units of $\frac{g}{c {m}^{3}}$ when dealing with a solid.

• The mass has units of grams, $g$.

• The volume will have units of $m L$ or $c {m}^{3}$

We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:

densityxxvolume=(mass)/(cancel"volume")xxcancel"volume"

$\textcolor{b l u e}{\text{Density}}$$\times$$\textcolor{b l u e}{\text{Volume = Mass}}$

$\frac{10.5 g}{\cancel{c {m}^{3}}} \times 965 \cancel{c {m}^{3}}$

Thus, the $A g$ has a mass of $1.01 \times {10}^{4} g$