The distance between #(x, 2)# and #(0,6)# is #5# units. What is the value of #x#?

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Answer 1 · 2016-08-16T20:32:37

The distance between the two points is

#d=sqrt((x-0)^2+(2-6)^2)=sqrt(x^2+16)#

Hence

#sqrt(x^2+16)=5#

#x^2+16=25#

#x^2=9#

#x=+-3#