The force applied against a moving object travelling on a linear path is given by $F(x)= x^2+4x$ . How much work would it take to move the object over $x in [0,2]$ ?

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Answer 1 · 2018-04-09T16:43:36

The work is $=32/3J$

The work done

$DeltaW=FDeltax$

THe force is $F(x)=x^2+4x$

$W=int_0^2(x^2+4x)dx$

$=[1/3x^3+2x^2]_0^2$

$=(8/3+8)-(0+0)$

$=32/3J$

The force applied against a moving object travelling on a linear path is given by F(x)= x^2+4xF(x)= x^2+4x. How much work would it take to move the object over x in [0,2] x in [0,2] ?