The force applied against an object moving horizontally on a linear path is described by #F(x)=x^3+ 3 #. By how much does the object's kinetic energy change as the object moves from # x in [ 3, 5 ]#?

1 Answer
Mar 9, 2016

Answer:

Use Work Energy Theorem:
#W_F = DeltaKE = [(x(x^3-12))/4]_3^5 = 130J#
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Explanation:

Use Work Energy Theorem:
#W_F = DeltaKE = 1/2mDeltav^2#
Now #W_F = intF*dr = int_3^5 F*dx = int_3^5 x^3+3*dx#
#W_F = [(x(x^3-12))/4]_3^5 = 130J #