# The gas in a container is at a pressure of 3.00 atm at 25°C. Directions on the container wam the user not to keep it in a place where the temperature exceeds 52°C. What would the gas pressure in the container be at 52°C?

Apr 13, 2017

The pressure is $= 3.27 a t m$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

The initial pressure, ${P}_{1} = 3.00 a t m$

The initial temperature ${T}_{1} = 25 + 273 = 298 K$

The final temperature ${T}_{2} = 52 + 273 = 325 K$

The final pressure is

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1}$

$= \frac{325}{298} \cdot 3 = 3.27 a t m$