The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #360 ^o K#. If the pressure in the container changes to #64 Pa# with no change in the container's volume, what is the new temperature of the gas?
1 Answer
Aug 18, 2017
Explanation:
We're asked to find the final temperature of a gas, given some pressure and temperature information.
To do this, we can use the pressuretemperature relationship of gases, illustrated by GayLussac's law:
#(P_1)/(T_1) = (P_2)/(T_2)" "# (constant volume and quantity of gas)
where

#P_1# and#P_2# are the initial and final pressures of the gas 
#T_1# and#T_2# are the initial and final absolute temperatures of the gas (which must be in Kelvin)
We know:

#P_1 = 12# #"Pa"# 
#P_2 = 64# #"Pa"# 
#T_1 = 360# #"K"# 
#T_2 = ?#
Plugging these in:
#(12color(white)(l)"Pa")/(360color(white)(l)"K") = (64color(white)(l)"Pa")/(T_2)#
#color(red)(ulbar(stackrel(" ")(" "T_2 = 1920color(white)(l)"K"" "))#