The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #30 ^o K#. If the temperature of the gas changes to #200 ^oK# with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Mar 5, 2016

Answer:

The new pressure of the gas will be #80 Pa#.

Explanation:

Pressure #P#, volume #V# and temperature #T# (in Kelvin) have the relation #PV/T=k# where #k# is a constant.

As there is no change in the container's volume, it means that #P_1/T_1=P_2/T_2#

In the given case, gas inside of a container exerts #12Pa# of pressure and is at a temperature of #30^oK#. When the temperature of the gas changes to #200^oK#, if the pressure becomes #P_2#, we should have

#12/30=P_2/200# or #P_2=((200xx12)/30)#

i.e. #P_2=2400/30=80# #Pa#.