# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 220 ^o C. If the temperature of the gas changes to 10 ^oC with no change in the container's volume, what is the new pressure of the gas?

Nov 18, 2016

The new pressure of the gas is 0.68 Pascals.

#### Explanation:

Considering the ideal gas equation
$P V = R T$(n=1)
We can know from the above equation that pressure is directly proportional to the temperature.
$\implies P \propto T$
this means $\frac{{P}_{1}}{{P}_{2}} = \frac{{T}_{1}}{{T}_{2}}$
calculating with given values we get,
$\implies \frac{15 P a}{{P}_{2}} = \frac{{220}^{o} C}{{10}^{o} C}$
So $\therefore$ the new pressure ${P}_{2} = 0.68$ Pascals$= 6.71 \times {10}^{-} 6 a t m = 5.1 \times {10}^{-} 3$torr.