# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 180 ^o K. If the pressure in the container changes to 36 Pa with no change in the container's volume, what is the new temperature of the gas?

Dec 7, 2016

The new temperature is $432 K$

#### Explanation:

We use Gaylussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

${P}_{1} = 15 P a$

${T}_{1} = 180 K$

${P}_{2} = 36 P a$

${T}_{2} = \frac{{P}_{2} {T}_{1}}{P} _ 1$

$= 36 \cdot \frac{180}{15} = 432 K$