The gas inside of a container exerts $15 Pa$ of pressure and is at a temperature of $180 ^o K$ . If the pressure in the container changes to $36 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2016-12-07T15:14:00

The new temperature is $432K$

We use Gaylussac's Law

$P_1/T_1=P_2/T_2$

$P_1=15Pa$

$T_1=180K$

$P_2=36Pa$

$T_2=(P_2T_1)/P_1$

$=36*180/15=432K$

The gas inside of a container exerts 15 Pa15 Pa of pressure and is at a temperature of 180 ^o K180 ^o K. If the pressure in the container changes to 36 Pa36 Pa with no change in the container's volume, what is the new temperature of the gas?