The gas inside of a container exerts 15 Pa15Pa of pressure and is at a temperature of 640 ^o K640oK. If the pressure in the container changes to 36 Pa36Pa with no change in the container's volume, what is the new temperature of the gas?

1 Answer
Nov 14, 2016

The final temperature will be 1500 K.

Explanation:

This question is an example of Guy-Lussac's law which states that the pressure of a given amount of gas held at constant volume, is directly proportional to its Kelvin temperature.

The equation to use is:
http://me-mechanicalengineering.com/gas-laws/http://me-mechanicalengineering.com/gas-laws/

Known
P_1="15 Pa"P1=15 Pa
T_1="640 K"T1=640 K
P_2="36 Pa"P2=36 Pa

Unknown
T_2T2

Solution
Rearrange the equation to isolate T_2T2. Substitute the known values into the equation and solve.

T_2=(P_2T_1)/P_1T2=P2T1P1

T_2=(36cancel"Pa"xx640"K")/(15cancel"Pa")="1500 K" rounded to two significant figures