# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 640 ^o K. If the pressure in the container changes to 36 Pa with no change in the container's volume, what is the new temperature of the gas?

Nov 14, 2016

The final temperature will be 1500 K.

#### Explanation:

This question is an example of Guy-Lussac's law which states that the pressure of a given amount of gas held at constant volume, is directly proportional to its Kelvin temperature.

The equation to use is:

Known
${P}_{1} = \text{15 Pa}$
${T}_{1} = \text{640 K}$
${P}_{2} = \text{36 Pa}$

Unknown
${T}_{2}$

Solution
Rearrange the equation to isolate ${T}_{2}$. Substitute the known values into the equation and solve.

${T}_{2} = \frac{{P}_{2} {T}_{1}}{P} _ 1$

T_2=(36cancel"Pa"xx640"K")/(15cancel"Pa")="1500 K" rounded to two significant figures