Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `640 ^o K`. If the pressure in the container changes to `36 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

The final temperature will be 1500 K.

Explanation:

This question is an example of Guy-Lussac's law which states that the pressure of a given amount of gas held at constant volume, is directly proportional to its Kelvin temperature.

The equation to use is:

Known
`P_1="15 Pa"`
`T_1="640 K"`
`P_2="36 Pa"`

Unknown
`T_2`

Solution
Rearrange the equation to isolate `T_2`. Substitute the known values into the equation and solve.

`T_2=(P_2T_1)/P_1`

`T_2=(36cancel"Pa"xx640"K")/(15cancel"Pa")="1500 K"` rounded to two significant figures