The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #640 ^o K#. If the pressure in the container changes to #36 Pa# with no change in the container's volume, what is the new temperature of the gas?

1 Answer
Nov 14, 2016

Answer:

The final temperature will be 1500 K.

Explanation:

This question is an example of Guy-Lussac's law which states that the pressure of a given amount of gas held at constant volume, is directly proportional to its Kelvin temperature.

The equation to use is:
http://me-mechanicalengineering.com/gas-laws/

Known
#P_1="15 Pa"#
#T_1="640 K"#
#P_2="36 Pa"#

Unknown
#T_2#

Solution
Rearrange the equation to isolate #T_2#. Substitute the known values into the equation and solve.

#T_2=(P_2T_1)/P_1#

#T_2=(36cancel"Pa"xx640"K")/(15cancel"Pa")="1500 K"# rounded to two significant figures