# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 275 ^o K. If the pressure in the container changes to 25 Pa with no change in the container's volume, what is the new temperature of the gas?

Aug 24, 2016

458.3 Kelvin (but there is no degrees sign)

#### Explanation:

1st situation: $P \cdot V = n \cdot R \cdot T$

Here we have 15 Pa and 275 Kelvin (n, V and R are constants)

$15 \cdot V = n \cdot R \cdot 275$

or $\frac{V}{n \cdot R} = \frac{275}{15}$

V((n*R) = 18.3

2nd situation:

(n, V and R constants)

$18.3 = \frac{T}{25}$ T is temperature in Kelvin

Then $T = 18.3 \cdot 25$

T = 458.3 Kelvin