# The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #450 ^o K#. If the temperature of the gas changes to #90 ^oK# with no change in the container's volume, what is the new pressure of the gas?

##### 1 Answer

Jun 13, 2016

#### Answer:

The new gas pressure is

#### Explanation:

For this type of question, you would use Gay-Lussac's Law

Gay-Lussac's Law shows that there is a direct relationship between *pressure* and *temperature* as long as the volume and number of moles of gas **remain unchanged**.

Let's start off with identifying our known and unknown variables.

The first pressure we have is

Now we just rearrange the equation in order to solve for

#P_2 = (T_2 * P_1)/(T_1)#

#P_2 = 3 Pa#

P.S. When using the Kelvin scale, you do not put the degree symbol. You just write K.