# The gas inside of a container exerts 18 Pa of pressure and is at a temperature of 350K. If the temperature of the gas changes to 240K with no change in the container's volume, what is the new pressure of the gas?

Oct 30, 2016

#### Answer:

$12.3428 p a$

#### Explanation:

in this case,
Gay Lussac's law will be applied as the volume stays constant.
from the law, we know that,
${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$
here,
${P}_{1} = 18 p a$
${T}_{1} = 350 k$
${T}_{2} = 240 k$
now, we have to find ${P}_{2}$
putting the values in the equation, we get,

$\frac{18}{350} = {P}_{2} / 240$
$\mathmr{and} , {P}_{2} = \frac{240 \cdot 18}{350}$
$\mathmr{and} , {P}_{2} = 12.3428 p a$