# The gas inside of a container exerts 24 Pa of pressure and is at a temperature of 85 ^o K. If the temperature of the gas changes to 17 ^oK with no change in the container's volume, what is the new pressure of the gas?

Jul 3, 2016

${P}_{l} = 4.8 \text{ } P a$

#### Explanation:

${P}_{i} : \text{initial pressure of gas ;"v_i=24" } P a$

P_l:"last pressure of gas ;"v_l=?

${T}_{i} : \text{initial temperature of gas ;"T_i=85" } {K}^{o}$

${T}_{l} : \text{last temperature of gas ;"T_l=17" } {K}^{o}$

${P}_{i} / {T}_{i} = {P}_{l} / {T}_{l}$

$\frac{24}{85} = {P}_{l} / 17$

${P}_{l} = \frac{24 \cdot 17}{85}$

${P}_{l} = 4.8 \text{ } P a$