# The gas inside of a container exerts "36 Pa" of pressure and is at a temperature of "75 K". If the temperature of the gas changes to "125 K" with no change in the container's volume, what is the new pressure of the gas?

Mar 29, 2017

The new pressure is $= 60 P a$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

Pressure, ${P}_{1} = 36 P a$

Temperature, ${T}_{1} = 75 K$

Temperature, ${T}_{2} = 125 K$

Pressure, ${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1}$

$= \frac{125}{75} \cdot 36 = 60 P a$