The gas inside of a container exerts $8 Pa$ of pressure and is at a temperature of $120 ^o K$ . If the pressure in the container changes to $64 Pa$ with no change in the container's volume, what is the new temperature of the gas?

Question

1284 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-10T10:27:51

For constant volume and mass we can apply Gay Lussac's law,

i.e $P/T$ = constant

So,let the final temperature be $T$

so,we can write, $64/T =c$ (where, $c$ is a constant)

again, from initial conditions of pressure and temperature we get,

$8/120 =c$

so, $64/T =8/120$

so, $T=960K$

The gas inside of a container exerts 8 Pa8 Pa of pressure and is at a temperature of 120 ^o K120 ^o K. If the pressure in the container changes to 64 Pa64 Pa with no change in the container's volume, what is the new temperature of the gas?