# The gas inside of a container exerts 8 Pa of pressure and is at a temperature of 120 ^o K. If the pressure in the container changes to 64 Pa with no change in the container's volume, what is the new temperature of the gas?

Mar 10, 2018

For constant volume and mass we can apply Gay Lussac's law,

i.e $\frac{P}{T}$ = constant

So,let the final temperature be $T$

so,we can write, $\frac{64}{T} = c$ (where, $c$ is a constant)

again, from initial conditions of pressure and temperature we get,

$\frac{8}{120} = c$

so, $\frac{64}{T} = \frac{8}{120}$

so, $T = 960 K$