Question

The gas inside of a container exerts `80 Pa` of pressure and is at a temperature of `420 ^o K`. If the pressure in the container changes to `72 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

`378^oK`

Explanation:

As there is no change in Volume `V`, `P/T` is always constant, where `P` is Pressure and `T` is Temperature in degree Kelvin.

As initially container exerts `80Pa` of pressure and is at a temperature of `420^oK`, `P/T=80/420`. As pressure in the container changes to `72Pa`, if Temperature changes to `T_1`

`72/T_1=80/420`

Hence `T_1=(72*420)/80=378^oK`