The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #35 ^o K#. If the temperature of the gas changes to #20 ^oK# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-06-05T03:23:59

#5# #"Pa"#

To solve this problem, we can use the pressure-temperature relationship of gases, illustrated by Gay-Lussac's law:

#(P_1)/(T_1)=(P_2)/(T_2)#

Let's rearrange this equation to solve for the final pressure, #P_2#:

#P_2 = (P_1T_2)/(T_1)#

Plugging in known values, we have

#P_2 = ((9"Pa")(20cancel("K")))/(35cancel("K")) = color(red)(5)# #color(red)("Pa"#

rounded to one significant figure, the lowest amount given in the problem.