The graph of #y=e^x/2# is the bisector-graph of the graphs for #y = cosh x and y = sinh x#. How do you use these graphs to show that the limit for the indeterminate form #oo-oo# could be 0?.
See the explanation.
The arithmetic mean
I have named the graph of #y =e^x/2 the bisector graph of the
graphs of y = cosh x and y = sinh x.
Use the separate limits:,