The kinetic energy of an object with a mass of $1 k g$ $1 kg$ constantly changes from $126 J$ $126 J$ to $702 J$ $702 J$ over $9 s$ $9 s$ . What is the impulse on the object at $5 s$ $5 s$ ?

Question

1584 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-16T12:52:45

Cannot be answered

$K . E . = k \cdot t$ $K.E. = k*t$

$\Rightarrow v = \sqrt{\frac{2 k}{m}} \sqrt{t}$ $=> v = sqrt((2k)/m) sqrt(t)$

$\Rightarrow \int_{i}^{f} m d v = \int_{t}^{t + 5} \sqrt{\frac{k}{2} m} \frac{d t}{\sqrt{t}}$ $=> int_i^f m dv = int_t^(t+5) sqrt(k/2m) dt/sqrt(t)$

So to have an absolute value of the impulse, we need to specify which 5s we are talking about.

The kinetic energy of an object with a mass of 1kg1 kg constantly changes from 126J126 J to 702J702 J over 9s9 s. What is the impulse on the object at 5s5 s?