# The kinetic energy of an object with a mass of 1 kg constantly changes from 126 J to 702 J over 9 s. What is the impulse on the object at 5 s?

Apr 16, 2016

$K . E . = k \cdot t$
$\implies v = \sqrt{\frac{2 k}{m}} \sqrt{t}$
$\implies {\int}_{i}^{f} m \mathrm{dv} = {\int}_{t}^{t + 5} \sqrt{\frac{k}{2} m} \frac{\mathrm{dt}}{\sqrt{t}}$