The kinetic energy of an object with a mass of #2 kg# constantly changes from #32 J# to #84 J# over #4 s#. What is the impulse on the object at #1 s#?

1 Answer
Apr 21, 2016

Answer:

#F*Delta t=2,1" " N*s#

Explanation:

#tan theta=(84-32)/4#

#tan theta=52/4=13#
#E=1/2*m*v^2" "v^2=(2E)/m" ; "v=sqrt((2E)/m)" ; "v=sqrtE#
#t=0" "E=32J" "v=5,66m/s#
#t=1" "E=32+13=45J" "v=6,71m/s#
#t=2" "E=45+13=58J" "v=7,62m/s#
#t=3" "E=58+13=71J" "v=8,43m/s#
#t=4" "E=71+13=84J" "v=9,17m/s#

#"impulse for t=1 "#
#F*Delta t=m(v(1)-v(0))#

#F*Delta t=2(6,71-5,66)#
#F*Delta t=2*1,05#
#F*Delta t=2,1" " N*s#