Question

The kinetic energy of an object with a mass of `3 kg` constantly changes from `50 J` to `270 J` over `5 s`. What is the impulse on the object at `3 s`?

Answer 1

`F*Delta t=4,27" "N*s`

Explanation:

`F*Delta t=m*Delta v`

`F*Delta t=3*(11,0151410946-9,5916630466)`

`F*Delta t=4,27" "N*s`