# The length of a rectangle is 4 cm more than its width. If the perimeter of the rectangle is 64 cm, how do you find the dimensions of the rectangle?

Sep 9, 2015

I found $14 c m \mathmr{and} 18 c m$

#### Explanation:

Call the length $l$ and the width $w$ so you have:
$l = w + 4$
now consider the perimeter $P$:
$P = 2 l + 2 w = 64 c m$
substitute for $l$
$2 \left(w + 4\right) + 2 w = 64$
$2 w + 8 + 2 w = 64$
$4 w = 56$
$w = \frac{56}{4} = 14 c m$
use this into the expression for $l$ you get:
$l = 14 + 4 = 18 c m$