The length of each side of square A is increased by 100 percent to make square B. Then each side of square is increased by 50 percent to make square C. By what percent is the area of square C greater than the sum of the areas of square A and B?

1 Answer
Jan 27, 2016

Answer:

Area of C is #80%# greater than area of A #+# area of B

Explanation:

Define as a unit of measurement the length of one side of A.

Area of A #= 1^2 = 1# sq.unit

Length of sides of B is #100%# more than length of sides of A
#rarr# Length of sides of B #=2# units
Area of B #=2^2 = 4# sq.units.

Length of sides of C is #50%# more than the length of sides of B
#rarr# Length of sides of C #=3# units
Area of C #=3^2 = 9# sq.units

Area of C is #9-(1+4) = 4# sq.units greater than the combined areas of A and B.

#4# sq.units represents #4/(1+4)=4/5# of the combined area of A and B.

#4/5 = 80%#