The only quadrant that contains no points of the graph of #y = -x^2 + 8x - 18# is which quadrant?

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Answer 1 · 2016-02-28T04:06:24

Quadrant 1 and 2 will not have points of #y=-x^2+8x-18#

Solve for the vertex
#y=-x^2+8x-18#

#y=-(x^2-8x+16-16)-18#

#y=-(x-4)^2+16-18#

#y+2=-(x-4)^2#

vertex at #(4, -2)#

graph{y=-x^2+8x-18[-20,40,-25,10]}

God bless....I hope the explanation is useful..