The only quadrant that contains no points of the graph of y = -x^2 + 8x - 18 is which quadrant?

Quadrant 1 and 2 will not have points of $y = - {x}^{2} + 8 x - 18$

Explanation:

Solve for the vertex
$y = - {x}^{2} + 8 x - 18$

$y = - \left({x}^{2} - 8 x + 16 - 16\right) - 18$

$y = - {\left(x - 4\right)}^{2} + 16 - 18$

$y + 2 = - {\left(x - 4\right)}^{2}$

vertex at $\left(4 , - 2\right)$

graph{y=-x^2+8x-18[-20,40,-25,10]}

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